Population is unknown and population parameters are also
unknown. In case of industrial applications, knowing the population is a very
expensive and time consuming process. So a sampling scheme is designed. We base
our judgment on the basis of a sample. This involves a risk of wrongfully
rejecting a good lot and wrongfully accepting a bad lot. The prior is called
producer’s risk and later is called consumer’s risk. With probability we can quantify
these risks. Yesterday’s example illustrated the quantification of producer’s
risk with the value of probability. These concepts are discussed further in
this example.
Example: A lot
contains 52 integrated chips (IC). A sample of 4 IC is selected at random from
each lot. According to the sampling scheme designed for quality control, if the
sample contains more than 2 defectives it is rejected. Due to the choice of a
bad supplier suppose the number of defective in a lot of 52 rise to 12 (this is
unknown to us). What is the probability that this lot is still accepted?
Solution: Let X be the number of defective IC in a lot of 4
defectives.
P(lot is accepted) = P( no of defectives less than or equal
to 2) = P(X=0) + P(X = 1) + P(X=2)
= [C(40, 4)/C(52, 4)]+[C(12, 1)C(40, 3)/C(50, 4)]+ [C(12,
2)C(40, 2)/C(50, 4)]
= 0.96
There is 96% chance that we can accept a lot with more than
10% of defective. Our objective is to have only 10% defectives in the
population. This is consumer’s risk as consumers can get these defective
products. The producer’s risk was quantified as 0.017% in yesterday’s example.
No comments:
Post a Comment